The graph gives information about the speed, v metres per second, of the car t seconds after it starts to move.
Worked Solution & Mark Scheme (4 marks)
Tangent at t = 15 has gradient ≈ 7.5 ÷ 9 = 0.83 M2 A1
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Free Printable Velocity time graphs PDF Worksheets, Revision Guide & GCSE Past Paper Questions (Grade 8+)
Download free velocity time graphs worksheets (PDF), GCSE maths past paper questions and worked solutions for Velocity time graphs (8G). This is a Grade 8+ algebra topic from the GCSE questions by topic collection for Foundation and Higher tier GCSE Maths (Edexcel, AQA, OCR and IGCSE).
The free PDF worksheets table below brings together printable question booklets (Qs) and worked answers or mark schemes (Ans) from Maths Genie, Corbett Maths, Maths Made Easy, Dr Frost, Naiker Maths, 1st Class Maths, Metatutor, Dr Austin, E Classroom and PMT, along with past paper question booklets.
Below the worksheet links you can read our velocity time graphs revision notes and worked examples with diagrams, try real GCSE past paper velocity time graphs questions with step-by-step solutions, or download a PDF of all velocity time graphs worksheet links.
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Explanation:
On a velocity-time graph, the gradient represents acceleration (change in velocity ÷ time) and the area under the graph represents distance travelled. For straight-line graphs, split the region into triangles and trapeziums; for curved graphs, draw a tangent at the given point to estimate instantaneous acceleration.
To estimate the distance under a curve using strips of equal width, split the area into a triangle and trapeziums: if the curve is concave down, the chords lie below the curve so your answer is an underestimate; if concave up, it is an overestimate.
Example 1: A car accelerates uniformly from rest to 20 m/s in 8 s, travels at 20 m/s for 15 s, then decelerates to rest in 5 s. Find the deceleration and total distance.
Solution:
Example 2: Velocity v (m/s) at t = 0, 2, 4, 6 s is 0, 5, 14, 27. Estimate the distance travelled in 6 s using 3 strips of equal width.
Solution: