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BIDMAS Quiz

Grade 1 • 1L • 10 Questions (25 Marks)

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Score: 0 / 10
BIDMAS — Notes & Worked Examples Show / Hide

Explanation:

BIDMAS gives the strict order of operations in mathematics: Brackets first, then Indices (powers and roots), then Division and Multiplication, and finally Addition and Subtraction.

Division and Multiplication have equal priority (work from left to right). Similarly, Addition and Subtraction have equal priority (work from left to right — do not automatically add before subtracting if subtraction comes first on the left).

Example 1: Work out 18 − 3 × 4 + 22

Solution:

1. Indices: 22 = 4 → 18 − 3 × 4 + 4
2. Multiply: 3 × 4 = 12 → 18 − 12 + 4
3. Add/Subtract (left to right):
• 18 − 12 = 6, then 6 + 4 = 10
Answer: 10

Example 2: Work out 36 ÷ (11 − 2) + 5 × 32

Solution:

1. Brackets: (11 − 2) = 9 → 36 ÷ 9 + 5 × 32
2. Indices: 32 = 9 → 36 ÷ 9 + 5 × 9
3. Divide & Multiply: 36 ÷ 9 = 4 and 5 × 9 = 45
4. Add: 4 + 45 = 49
Answer: 49
Question 1
[1 mark]
Alec needs to work out the value of 2 + 3 × 4
He writes
2 + 3 = 5 and 5 × 4 = 20, so 2 + 3 × 4 = 20
Alec is wrong.
Explain why.
Worked Solution & Answer
Multiplication must be done before addition (2 + 12 = 14) C1
Answer: He should multiply 3 × 4 first (using BIDMAS), giving 2 + 12 = 14
Question Paper (PDF) • Mark Scheme (PDF)
Question 3
[1 mark]
Olly was asked to work out 5 - 3 × 4
Olly wrote 5 - 3 = 2
He then worked out 2 × 4
Explain what is wrong with Olly’s method.
Worked Solution & Answer
Multiplication must be done before subtraction (BIDMAS) C1
Answer: He should have multiplied 3 by 4 first before subtracting from 5 (5 – 12 = –7)
Question Paper (PDF) • Mark Scheme (PDF)
Question 4 OCR Nov 2020 3F Q3
[2 marks]
Alex has a number game.
He must put down tiles to make two calculations with the same answer.
Here is what Alex put down.
2−3×2=3−5
Is he correct?
Show how you decide.
Worked Solution & Answer
Left side: 2 − (3 × 2) = 2 − 6 = −4. M1
Right side: 3 − 5 = −2.
Since −4 ≠ −2, Alex is incorrect. C1
Answer: Alex is incorrect because 2 − 3 × 2 = 2 − 6 = −4 whereas 3 − 5 = −2.
Question Paper (PDF) • Mark Scheme (PDF)
Question 5 OCR Nov 2022 3F Q3
[2 marks]
(a) Insert brackets to make this calculation correct.
5 - 5 × 5 = 0
(b) Insert **two** of these symbols +, -, × or ÷ to make this calculation correct.
20 … 5(1 … 3) = 0
(a) Insert brackets to make this calculation correct.
5 - 5 × 5 = 0 [1 mark]
(b) Insert **two** of these symbols +, -, × or ÷ to make this calculation correct.
20 … 5(1 … 3) = 0 [1 mark]
Worked Solution & Answer
(a)
(5 − 5) × 5 = 0 × 5 = 0. B1
Answer (a): (5 - 5) × 5 = 0
(b)
20 − 5(1 + 3) = 20 − 5 × 4 = 20 − 20 = 0. B1
Answer (b): 20 - 5(1 + 3) = 0
Question Paper (PDF) • Mark Scheme (PDF)
Question 6 OCR Jun 2023 2F Q2
[2 marks]
Work out
(a) Work out.
20 - 16 ÷ 2
(b) Insert **one** pair of brackets to make this calculation correct.
(a) Work out.
20 - 16 ÷ 2 [1 mark]
(b) Insert **one** pair of brackets to make this calculation correct. [1 mark]
2 + 7 − 3 × 8 = 34
Worked Solution & Answer
(a)
16 ÷ 2 = 8
20 − 8 = 12. B1
Answer (a): 12
(b)
2 + (7 − 3) × 8 = 2 + 4 × 8 = 2 + 32 = 34. B1
2 + (7 − 3) × 8 = 34
Answer (b): 2 + (7 − 3) × 8 = 34
Question Paper (PDF) • Mark Scheme (PDF)
Question 7 OCR Jun 2025 2F Q6
[3 marks]
(a) (i) 10 - 2 × 3
(ii) -1 + 32
(b) Insert **one** pair of brackets to make this calculation correct.
6 × 10 ÷ 2 - 4 = 6
(a) 10 - 2 × 3 [1 mark]
(b) -1 + 32 [1 mark]
(b) Insert **one** pair of brackets to make this calculation correct.
6 × 10 ÷ 2 - 4 = 6 [1 mark]
Worked Solution & Answer
(a)
10 − 6 = 4. B1
Answer (a): 4
(b)
−1 + 9 = 8. B1
Answer (b): 8
(b)
10 ÷ 2 − 4 = 5 − 4 = 1, and 6 × 1 = 6 ⇒ 6 × (10 ÷ 2 − 4) = 6. B1
Answer (b): 6 × (10 ÷ 2 - 4) = 6
Question Paper (PDF) • Mark Scheme (PDF)
Question 8 IGCSE Jun 2023 2F Q15
[4 marks]
Finn is asked to find the value of 5 + 32 + 12
Here is his working and his answer.
5 + 32 + 12 = 82 + 12
= 64 + 12
= 76
Finn's answer is wrong.
(a) Explain what Finn has done wrong in his working. [1 mark]
(b) Write one pair of brackets in this calculation so that the answer is correct.
2 × 6 - 42 - 14 = 10 [1 mark]
(c) Work out the value of x2 + 5y when x = -3 and y = 2 [2 marks]
Worked Solution & Answer
(a)
He added 5 and 3 first instead of squaring 3 first
Answer (a): He added 5 and 3 first instead of squaring 3 first
(b)
12 – (16 – 14) = 12 – 2 = 10 B1
Answer (b): 2 × 6 - (42 - 14) = 10
(c)
(–3)² + 5(2) = 9 + 10 = 19 M1 A1
Answer (c): 19
Question Paper (PDF) • Mark Scheme (PDF)
Question 9 IGCSE Jun 2022 2FR Q6
[4 marks]
(a)(i) √31.36 (1) (ii) 14³ (1) (b)(i) 10 – ... × 2 = 4 (1) (ii) (5 + ...) × 3 = 36 (1)
(a) √(31.36) [1 mark]
(b) 143 [1 mark]
(b) 10 - ………… × 2 = 4 [1 mark]
(d) (5 + …………) × 3 = 36 [1 mark]
Worked Solution & Answer
(a)
5.6
Answer (a): 5.6
(b)
2744
Answer (b): 2744
(b)
10 – 6 = 4 ⇒ 3 × 2 = 6 B1
Answer (b): 3
(d)
36 ÷ 3 = 12 ⇒ 5 + 7 = 12 B1
Answer (d): 7
Question Paper (PDF) • Mark Scheme (PDF)
Question 10 IGCSE Jun 2024 2FR Q6
[5 marks]
(a) 3.4² (1) (b) Cube root of 373 248 (1) (c) 7×7×7×7×7÷7 as power of 7 (1) (d) Add brackets: (i) 5 + 3 × 2 = 16 (1) (ii) 10 − 8 − 10 − 6 ÷ 2 = 0 (1)
(a) Find the value of 3.42 [1 mark]
(b) Find the cube root of 373 248 [1 mark]
(c) Write 7 × 7 × 7 × 7 × 7 ÷ 7 as a single power of 7 [1 mark]
(d) 5 + 3 × 2 = 16 [1 mark]
(e) 10 - 8 - 10 - 6 ÷ 2 = 0 [1 mark]
Worked Solution & Answer
(a)
3.4² = 11.56 B1
Answer (a): 11.56
(b)
∛373248 = 72 B1
Answer (b): 72
(c)
7⁵ ÷ 7¹ = 7⁴ B1
Answer (c): 74
(d)
(5+3)×2 = 16
Answer (d): (5 + 3) × 2 = 16
(e)
10 − 8 − (10−6)÷2 = 2 − 4÷2 = 0 B1
Answer (e): 10 − 8 − (10 − 6) ÷ 2 = 0
Question Paper (PDF) • Mark Scheme (PDF)
Score: 0 / 10 (0 / 25 marks)
BIDMAS Worksheets Next: Factors, multiples and primes →

Grade 1 Quizzes

16 Topics
1A - Addition1B - Subtraction
1C - Multiplication1D - Division
1E - Time1F - Ordering FDP
1G - Place Value1H - Rounding
1J - Negative numbers1K - Powers and roots
1L - BIDMAS1M - Factors, multiples and primes
1N - Coordinates1P - Pictograms
1Q - 2D shapes1R - 3D shapes