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Score: 0 / 10
xy–551015–15–10–55O2y = 3x – 222 – 2y = x
Use the graphs to solve the simultaneous equations 2 – 2y = x and 2y = 3x – 22.
Use these graphs to solve the simultaneous equations
2 - 2y = x
2y = 3x - 22
Worked Solution & Answer
The lines intersect at (6, –2) B1
Answer: x = 6, y = –2
Question 2 5K Cubic/reciprocal graphs OCR Nov 2022 5H Q21
[1 mark]
The graph of y = 1x - 2 is drawn on the grid for -2 ≤ x ≤ 6.
–2–10123456–5–4–3–2–112345678910xy
(a) There are no values of x for which 1x - 2 = k.
Find the value of k.
[1 mark]
k =
Worked Solution & Answer
(a)
The horizontal asymptote is y = 0, so 1/(x − 2) never equals 0 ⇒ k = 0. B1
Answer (a): k = 0
[2 marks]
xy–5–4–3–2–112345–5–4–3–2–112345OPQ
Find the coordinates of the midpoint of PQ where P = (–3, –2) and Q = (2, 4).
Find the coordinates of the midpoint of PQ.
Worked Solution & Answer
((–3 + 2)/2, (–2 + 4)/2) = (–0.5, 1) M1 A1
Answer: (–0.5, 1)
[2 marks]
Here is the graph of y = x2 - 2x - 2
xy–2–11234–4–3–2–11234O
(a) Write down the coordinates of the turning point on the graph of y = x2 - 2x - 2 [1 mark]
(b) Write down an estimate for one of the roots of x2 - 2x - 2 = 0 [1 mark]
Worked Solution & Answer
(a)
Minimum at (1, –3) B1
Answer (a): (1, –3)
(b)
x-intercepts at x ≈ –0.7 and x ≈ 2.7 B1
Answer (b): –0.7 or 2.7
Question 5 5C Reverse percentages AQA Nov 2021 3H Q14
[3 marks]
Phil sells ties.
He increases the original price of each tie by 10% to £13.20
A month later he announces a sale: 10% OFF ALL TIES.
SALE10% OFFALL TIES
Phil says,
“The ties will be back to their original price, because each change was by 10%”
Is he correct?
Tick a box: [ ] Yes [ ] No
Show working to support your answer.
Worked Solution & Answer
Original price = £13.20 ÷ 1.10 = £12.00 M1
Sale price = £13.20 × 0.90 = £11.88 M1
Since £11.88 ≠ £12.00, Phil is incorrect (tick No). A1
Answer: No, sale price is £11.88 whereas original price was £12.00
Question 6 5D Standard form IGCSE Jan 2022 2HR Q10
[3 marks]
The table gives information about the population and the total amount of money, in dollars, spent on healthcare for two countries in 2016
CountryTotal populationTotal spent on healthcare ($)Austria8.7 × 1064.2 × 1010Luxembourg6.3 × 1053.7 × 109
Work out how much more was spent per person on healthcare in Luxembourg than in Austria.
Give your answer correct to the nearest whole number.
dollars
Worked Solution & Answer
Luxembourg per person = (3.7 × 10⁹) ÷ (6.3 × 10⁵) = $5873.0158.. M1
Austria per person = (4.2 × 10¹⁰) ÷ (8.7 × 10⁶) = $4827.5862.. M1
Difference = 5873.0158 – 4827.5862 = 1045.429... → 1045 dollars. A1
Answer: 1045 dollars
[3 marks]
(a) Ben makes m subject of p = m/3 + 5: p – 5 = m/3; 3 × p – 5 = m; m = 3p – 5. What mistake has Ben made? (1)
(b) Factorise fully 2x³y + 4xy² (2)
(a) What mistake has Ben made? [1 mark]
(b) Factorise fully 2x3 y + 4xy2 [2 marks]
Worked Solution & Answer
(a)
When multiplying both sides by 3, the entire left hand side must be multiplied: 3(p – 5) = 3p – 15, not 3p – 5 B1
Answer (a): He didn't multiply the –5 by 3 (should be 3(p – 5) or 3p – 15)
(b)
Common factor is 2xy: 2xy(x² + 2y) M1 A1
Answer (b): 2xy(x2 + 2y)
Question 8 5H Solving quadratic equations AQA Jun 2025 1F Q26 / 1H Q10
[4 marks]
Not drawnaccurately(x + 2) cm(x – 5) cm
Rectangle with sides (x + 2) cm and (x – 5) cm has area 120 cm². Work out x. [4 marks]
The area of the rectangle is 120 cm2
Work out the value of x.
x =
Worked Solution & Answer
(The area of a rectangle is length × width)
(x + 2)(x – 5) = 120 ⇒ x² – 3x – 10 = 120 ⇒ x² – 3x – 130 = 0. M3
Factorise: (x – 13)(x + 10) = 0 ⇒ x = 13 (length > 0). A1
Answer: x = 13
[5 marks]
A pattern is made from four identical rectangles.
The sides of the rectangles are parallel to the axes.
xyOA(3, 4)CB(11, 20)
Point A has coordinates (3, 4)
Point B has coordinates (11, 20)
Point C is marked on the diagram.
Work out the coordinates of C.
You must show all your working.
Worked Solution & Answer
Let length = L and width = W M2
Horizontal change from A(3,4) to B(11,20): 2L – W = 11 – 3 = 8. Vertical change from A(3,4) to B(11,20): 2L + W = 20 – 4 = 16 M2
Adding gives 4L = 24 ⇒ L = 6, W = 4. Therefore C = (3 + L, 4 + W) = (3 + 6, 4 + 4) = (9, 8). A1
Answer: (9, 8)
Question 10 5G Quadratic expressions IGCSE Jan 2023 1F Q25
[6 marks]
(a) Factorise y² − 2y − 48 (2) (b) Write down the inequality shown on the number line (1) (c) Solve 7w + 6 > 12w + 14 (3)
(a) Factorise y2 - 2y - 48 [2 marks]
(b) Write down the inequality shown on the number line [1 mark]
x–2–1012345
(c) Solve the inequality 7w + 6 > 12w + 14 [3 marks]
Worked Solution & Answer
(a)
Numbers multiplying to −48 and adding to −2 are +6 and −8 M1
⇒ (y + 6)(y − 8) A1
Answer (a): (y + 6)(y - 8)
(b)
Filled circle at 3 pointing left ⇒ x ≤ 3 B1
Answer (b): x ≤ 3
(c)
6 − 14 > 12w − 7w M1
⇒ −8 > 5w M1
⇒ w < −8/5 A1
Answer (c): w < -85
Score: 0 / 10 (0 / 30 marks)