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Pressure Quiz

Grade 5 • 5AA • 10 Questions (27 Marks)

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Pressure — Notes & Worked Examples Show / Hide

Explanation:

Pressure, force and area are linked by Pressure = ForceArea, Force = Pressure × Area, and Area = ForcePressure. Force is measured in Newtons (N) and area in m2 or cm2, giving pressure in N/m2 (Pascals, Pa) or N/cm2.

Remember that Area is only the flat contact area touching the ground, not the total surface area of the 3D object. A smaller contact area produces a greater pressure for the same force.

Example 1: A crate of weight 1080 N rests on a rectangular base measuring 1.5 m by 0.8 m. Work out the pressure on the floor in N/m2.

Solution:

Base area = 1.5 × 0.8 = 1.2 m2
P = 1080 ÷ 1.2 = 900
Answer: 900 N/m2
1080 N 1.5 m 0.8 m

Example 2: A cylinder of radius 4 cm stands flat on a table and exerts a pressure of 2.5 N/cm2. Find the force exerted on the table (to 1 d.p.).

Solution:

Area = π(42) = 16π cm2
F = 2.5 × 16π = 40π N
Answer: 125.7 N (1 d.p.)
F r = 4 cm
Question 1
[1 mark]
@@TABULAR0@@
A box exerts a force of 90 N on a table
The area of the base of the box is 5 m²
Calculate the pressure exerted by the box
N/m²
Worked Solution & Answer
Pressure = ForceArea,   Force = Pressure × Area
18 N/m²
Answer: 18 N/m² N/m²
Question 2
[1 mark]
A cylinder rests on the ground with an area of 5 m²
It exerts a pressure of 50 N/m²
Calculate the force exerted by the cylinder
N
Worked Solution & Answer
(Pressure = force ÷ area) B1
Answer: 250 N N
Question 3
[2 marks]
pressure =forcearea
Work out
A storage tank exerts a force of 10 000 newtons on a 4 m by 2 m rectangular base. Work out the pressure.
A storage tank exerts a force of 10 000 newtons on the ground.
The base of the tank in contact with the ground is a 4 m by 2 m rectangle.
Work out the pressure on the ground due to the tank.
newtons/m²
Worked Solution & Answer
Area = 4 × 2 = 8 m² M1
Pressure = 10 000 ÷ 8 = 1250 newtons/m² A1
Answer: 1250 newtons/m²
Question Paper (PDF) • Mark Scheme (PDF)
Question 4
[3 marks]
A box in the shape of a cuboid is placed on a horizontal floor.
The box exerts a force of 180 newtons on the floor.
The box exerts a pressure of 187.5 newtons/m2 on the floor.
pressure =forcearea
The face in contact with the floor is a rectangle of length 1.2 metres and width x metres.
Work out the value of x.
x =
Worked Solution & Answer
(Pressure = force ÷ area)
Area = 180 ÷ 187.5 = 0.96 m² M2
1.2x = 0.96 ⇒ x = 0.96 ÷ 1.2 = 0.8 A1
Answer: x = 0.8
Question Paper (PDF) • Mark Scheme (PDF)
Question 5 Specimen Set 1 1H Q2
[3 marks]
A box exerts a force of 140 newtons on a table.
The pressure on the table is 35 newtons/m².
p=FAp = pressureF = forceA = area
Calculate the area of the box that is in contact with the table.
m²
Worked Solution & Answer
(Pressure = force ÷ area)
35 = 140 / A M2
⇒ A = 140 ÷ 35 = 4 m² A1
Answer: 4 m2 m²
Question Paper (PDF) • Mark Scheme (PDF)
Question 6
[3 marks]
The diagram shows a solid triangular prism on a horizontal floor.
2 mpressure =forcearea
The face in contact with the floor is a rectangle of width 2 m.
The pressure on the floor due to the prism is 80 newtons/m2
The force exerted by the prism on the floor is 720 newtons.
Work out the length of the prism.
m
Worked Solution & Answer
Area = 720 ÷ 80 = 9 m² M2
Length = 9 ÷ 2 = 4.5 m A1
Answer: 4.5 m
Question Paper (PDF) • Mark Scheme (PDF)
Question 7
[3 marks]
A force of 70 newtons acts on an area of 20 cm2
pressure =forcearea
The force is increased by 10 newtons.
The area is increased by 10 cm2
Helen says,
"The pressure decreases by less than 20%"
Is Helen correct?
You must show how you get your answer.
Worked Solution & Answer
Initial pressure = 70 ÷ 20 = 3.5 N/cm² M1
New pressure = (70 + 10) ÷ (20 + 10) = 80 ÷ 30 = 2.67 N/cm² M1
Percentage decrease = ((3.5 – 2.667) ÷ 3.5) × 100 = 23.8% > 20% (or 0.8 × 3.5 = 2.8 > 2.67), so Helen is not correct. A1
Answer: No, the pressure decreases by 23.8% (which is more than 20%)
Question Paper (PDF) • Mark Scheme (PDF)
Question 8 IGCSE Jan 2020 2FR Q23
[3 marks]
The diagram shows a box in the shape of a cuboid.
1.2 mx mDiagram NOTaccurately drawn
The box is put on a table.
The face of the box in contact with the table has length 1.2 metres and width x metres.
The force exerted by the box on the table is 27 newtons.
The pressure on the table due to the box is 30 newtons/m2
pressure = forcearea
Work out the value of x.
x =
Worked Solution & Answer
(Pressure = force ÷ area)
30 = 27 / (1.2x) M1
⇒ 1.2x = 27 / 30 = 0.9 M1
⇒ x = 0.9 ÷ 1.2 = 0.75 A1
Answer: x = 0.75
Question Paper (PDF) • Mark Scheme (PDF)
Question 9 IGCSE Jun 2022 1F Q22 / 1H Q7
[4 marks]
A cylinder is placed on the ground.
18 cmDiagram NOTaccurately drawn
The height of the cylinder is 18 cm.
The force exerted by the cylinder on the ground is 72 newtons.
The pressure on the ground due to the cylinder is 1.4 newtons/cm2
@@TABULAR0@@
Work out the volume of the cylinder.
Give your answer correct to 3 significant figures.
cm³
Worked Solution & Answer
Area of base = 72 ÷ 1.4 = 360/7 ≈ 51.4286 cm² M3
Volume = base area × height = (360/7) × 18 = 6480/7 = 925.71... ≈ 926 cm³ A1
Answer: 926 cm³
Question Paper (PDF) • Mark Scheme (PDF)
Question 10 IGCSE Jan 2020 1H Q13
[4 marks]
The diagram shows a solid cube.
The cube is placed on a table so that the whole of one face of the cube is in contact with the table.
w cmw cmw cmDiagram NOTaccurately drawn
The cube exerts a force of 56 newtons on the table.
The pressure on the table due to the cube is 0.14 newtons/cm2
pressure = forcearea
Work out the volume of the cube.
cm³
Worked Solution & Answer
(Pressure = force ÷ area)
Area of one face w² = 56 ÷ 0.14 = 400 cm² ⇒ w = √400 = 20 cm M3
Volume = 20³ = 8000 cm³ A1
Answer: 8000 cm³
Question Paper (PDF) • Mark Scheme (PDF)
Score: 0 / 10 (0 / 27 marks)
Pressure Worksheets Next: Recurring decimals →

Grade 5 Quizzes

25 Topics
5A - Combining ratios5B - Direct and inverse proportion
5C - Reverse percentages5D - Standard form
5E - Speed5F - Changing the subject
5G - Quadratic expressions5H - Solving quadratic equations
5J - Drawing quadratic graphs5K - Cubic/reciprocal graphs
5L - Simultaneous equations5M - Sector areas and arc lengths
5N - Sim. equ. graphically5P - Midpoint of a line segment
5Q - Gradient of a line5R - Equation of a line
5S - Spheres and cones5T - Similar shapes (lengths)
5U - Trigonometry (SOHCAHTOA)5V - Exact trig. values
5W - Probability trees5X - Vectors
5Y - Venn diagrams5Z - Density
5AA - Pressure