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Proportion (harder) Quiz

Grade 7 • 7C • 10 Questions (28 Marks)

Score: 0 / 10
Proportion (harder) — Notes & Worked Examples Show / Hide

Explanation:

Translate the proportion statement into an algebraic equation using a constant of proportionality k: if y is directly proportional to xn, write y = kxn; if y is inversely proportional to xn, write y = kxn. Substitute the given pair of values to find k and write the full formula before finding any unknown values.

For compound three-variable problems (where y depends on x and x depends on z), substitute the second formula directly into the first and simplify the powers and constants carefully. Remember to take both roots or the positive physical root when solving for x2 or √x.

Example 1: y is inversely proportional to x2. Given y = 5 when x = 6, find x when y = 20 (x > 0).

Solution:

y = kx2 ⇒ 5 = k62
k = 5 × 36 = 180, so y = 180x2
When y = 20: 20 = 180x2 ⇒ x2 = 18020 = 9
Since x > 0, x = √9 = 3
Answer: x = 3

Example 2: P = 3Q2 and Q is inversely proportional to √R. Given Q = 4 when R = 9, write P in terms of R.

Solution:

Q = k√R ⇒ 4 = k√9 ⇒ k = 4 × 3 = 12
Substitute Q = 12√R into P = 3Q2:
P = 3 × (12√R)2 = 3 × 144R
Answer: P = 432R
Question 1
[1 mark]
y is directly proportional to x2.
Given that y = 45 when x = 3, find the value of y when x = 6.
y =
Worked Solution & Answer
y = kx2 ⇒ 45 = k(32) ⇒ k = 5
When x = 6, y = 5(62) = 180. B1
Answer: y = y = 180
Question 2
[1 mark]
4 identical machines take 10 hours to print a batch of leaflets
How long would it take 5 of these machines?
hours
Worked Solution & Answer
1) Multiply the number of workers/machines by the time taken to find the total work required for 1 worker/machine
2) Divide that total by the new number of workers/machines (or new time)
8 hours
Answer: 8 hours hours
Question 3
[2 marks]
Work out
(a) Sketch graph for y is directly proportional to x (1) (b) Sketch graph for y is inversely proportional to x (1)
(a) Using the axes below, sketch a graph to represent the statement
y is directly proportional to x
[1 mark]
xyO
(b) Using the axes below, sketch a graph to represent the statement
y is inversely proportional to x
[1 mark]
xyO
Worked Solution & Answer
(a)
y = kx is a straight line through (0, 0) B1
xyO
Answer (a): Straight line with positive gradient passing through the origin O
(b)
y = k/x is a decreasing hyperbola in quadrant 1 B1
xyO
Answer (b): Reciprocal curve y = k/x in the first quadrant asymptotic to both axes
Question 4 OCR Nov 2023 4H Q8
[2 marks]
Here are sketches of six graphs, labelled **A** to **F**.
AyxOByxOCyxODyxOEyxOFyxO
(a) y is directly proportional to x. [1 mark]
(b) y is inversely proportional to x. [1 mark]
Worked Solution & Answer
(a)
Direct proportion y = kx is a straight line through the origin ⇒ Graph C. B1
Answer (a): C
(b)
Inverse proportion y = k/x is a reciprocal curve in the first quadrant ⇒ Graph E. B1
Answer (b): E
Question 5 OCR Nov 2018 3F Q24 / 6H Q9
[2 marks]
These graphs show different relationships between the variables x and y.
Graph AOxyGraph BOxyGraph COxyGraph DOxy
(a) Identify the graph which shows the following.
y is directly proportional to x.
[1 mark]
(b) y is inversely proportional to x. [1 mark]
Worked Solution & Answer
(a)
Direct proportion y = kx is a straight line through the origin ⇒ Graph A. B1
Answer (a): A
(b)
Inverse proportion y = k/x is a reciprocal hyperbola ⇒ Graph C. B1
Answer (b): C
Question 6
[3 marks]
p is inversely proportional to t
tp10012552
Complete the table of values.
Worked Solution & Answer
p × t = 100 × 1 = 100 ⇒ when t = 25, p = 4 M1
when p = 5, t = 20 M1
when t = 2, p = 50 A1
tp1001254205250
Answer: t = 20; p = 4, 50
Question 7 OCR Jun 2023 1F Q22
[4 marks]
Hiro and Taylor are both electricians.
Hiro **does not** charge to visit a house but charges a fixed rate per hour for the work needed.
This graph shows the relationship between the hours worked and the total charge made by Hiro.
OTotalchargeHours worked
(a) Explain how this graph shows that Hiro’s total charge is directly proportional to the hours worked. [2 marks]
(b) Taylor **does** charge to visit a house and charges the same fixed rate per hour as Hiro for the work needed.
On the axes above, draw a graph to show the relationship between the hours worked and the total charge made by Taylor.
[2 marks]
Worked Solution & Answer
(a)
A graph showing direct proportion must be a straight line through the origin. M1 C1
Answer (a): It is a straight line that passes through the origin (0, 0).
(b)
Same hourly rate ⇒ same gradient (parallel line) M1
call-out charge ⇒ positive y-intercept. A1
Answer (b): Straight line parallel to Hiro’s line with a positive vertical intercept.
Question 8
[4 marks]
The table shows a set of values for x and y.
x1234y92141916
(a) Find an equation for y in terms of x. [2 marks]
y =
(b) Find the positive value of x when y = 16 [2 marks]
Worked Solution & Answer
(a)
y = k/x² M1
Substitute x = 1, y = 9 ⇒ k = 9, so y = 9/x² A1
Answer (a): y = y = 9x2
(b)
16 = 9/x² M1
⇒ x² = 9/16
⇒ x = 3/4 A1
Answer (b): 34
Question 9 Specimen Set 2 3F Q27
[4 marks]
At a depth of x metres, the temperature of the water in an ocean is T °C.
At depths below 900 metres, T is inversely proportional to x.
T is given by
T = 4500x
(a) Work out the difference in the temperature of the water at a depth of 1200 metres and the temperature of the water at a depth of 2500 metres. [3 marks]
°C
(b) One of the graphs could show that T is inversely proportional to x.
Write down the letter of this graph.
[1 mark]
ATOxBTOxCTOxDTOx
Worked Solution & Answer
(a)
At x = 1200, T = 4500 ÷ 1200 = 3.75 °C M1
at x = 2500, T = 4500 ÷ 2500 = 1.8 °C M1
Difference = 3.75 – 1.8 = 1.95 °C A1
Answer (a): 1.95 °C
(b)
Graph D is the reciprocal curve y = k/x B1
Answer (b): D
Question 10
[5 marks]
Here is a table of values of x and y.
xy204468812
(a) Is Nadia correct?
You must give a reason for your answer.
[1 mark]
(b) Calculate the value of w when t = 7.84 [3 marks]
w =
(c) On the axes below, sketch a graph to show the relationship between w and t. [1 mark]
wtO
Worked Solution & Answer
(a)
No, because y is not a constant multiple of x (e.g. when x = 2, y = 0 so the graph does not pass through (0, 0) / 4 ÷ 4 ≠ 8 ÷ 6)
Answer (a): No, because y is not a constant multiple of x (e.g. when x = 2, y = 0 so the graph does not pass through (0, 0) / 4 ÷ 4 ≠ 8 ÷ 6)
(b)
w = k√t ⇒ 140 = k√64 = 8k ⇒ k = 17.5 M2
w = 17.5 × √7.84 = 17.5 × 2.8 = 49 A1
Answer (b): w = 49
(c)
Curve starting at (0, 0) with positive, decreasing gradient (w = k√t)
wtO
Answer (c): Curve starting at (0, 0) with positive, decreasing gradient (w = k√t)
Score: 0 / 10 (0 / 28 marks)
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