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Straight line graphs Quiz

Grade 3 • 3Q • 10 Questions (29 Marks)

Score: 0 / 10
Straight line graphs — Notes & Worked Examples Show / Hide

Explanation:

Every straight line has an equation of the form y = mx + c, where m is the gradient (steepness) and c is the y-intercept (where the line crosses the y-axis at (0, c)). To draw a straight-line graph, substitute each x-value into the equation to complete a table of values, plot the coordinates, and join them with a ruler.

To find the gradient m from a drawn line, pick two clear grid points on the line and calculate Gradient = Change in y (Rise)Change in x (Run). Lines sloping downwards from left to right have a negative gradient.

Example 1: Complete the table and draw y = 2x − 3.

x y 3 3 −3
x−10123
y−5−3−113
x = −1: 2(−1)−3 = −5
x = 1: −1;  x = 3: 3

Example 2: A line passes through (0, 4) and (2, 10). Find its equation in the form y = mx + c.

4 10 2 +2 +6
y-intercept: c = 4
m = 10 − 42 − 0 = 62 = 3
Answer: y = 3x + 4
Question 1
[2 marks]
x–3–2–10123y–3–2–1123–5–4–3–2–11234567891011120xy
Complete the table of values for:
y = x - 1
On the grid, draw the graph of y = x - 1 for values of x from -3 to 3.
Worked Solution & Answer
Substitute each x-value into the equation (use brackets around negative numbers).
y = -4, -3, -2, -1, 0, 1, 2
x–3–2–10123y–4–3–2–1012–3–2–1123–5–4–3–2–11234567891011120xy
Answer: y = -4, -3, -2, -1, 0, 1, 2
Question 2
[2 marks]
x–3–2–10123y–3–2–1123–5–4–3–2–11234567891011120xy
Complete the table of values for:
y = 2x + 2
On the grid, draw the graph of y = 2x + 2 for values of x from -3 to 3.
Worked Solution & Answer
Substitute each x-value into the equation (use brackets around negative numbers).
y = -4, -2, 0, 2, 4, 6, 8
x–3–2–10123y–4–202468–3–2–1123–5–4–3–2–11234567891011120xy
Answer: y = -4, -2, 0, 2, 4, 6, 8
Question 3 IGCSE Jan 2020 1FR Q11
[3 marks]
On the grid, draw the graph of y = 3x + 2 for values of x from -2 to 4
yx−2−11234O−5−4−3−2−11234567891011121314
Worked Solution & Answer
Points: (–2, –4), (–1, –1), (0, 2), (1, 5), (2, 8), (3, 11), (4, 14) M2 A1
yx−2−11234O−5−4−3−2−11234567891011121314
Answer: Straight line drawn from (−2, −4) to (4, 14)
Question 4 IGCSE Jun 2019 1FR Q11
[3 marks]
yx–2–1123456–7–6–5–4–3–2–11234567O
On the grid, draw the graph of y = 2x - 3 for values of x from –1 to 5
Worked Solution & Answer
Points: (–1, –5), (0, –3), (1, –1), (2, 1), (3, 3), (4, 5), (5, 7) M2 A1
yx–2–1123456–7–6–5–4–3–2–11234567O
Answer: Straight line drawn from (–1, –5) to (5, 7)
Question 5 IGCSE Specimen 1F Q12
[3 marks]
–2–1123–9–8–7–6–5–4–3–2–1123456789Oxy
On the grid, draw the graph of y = 1 - 3x for values of x from -2 to 3
Worked Solution & Answer
Points: (–2, 7), (–1, 4), (0, 1), (1, –2), (2, –5), (3, –8). M2 A1
–2–1123–9–8–7–6–5–4–3–2–1123456789Oxy
Answer: Straight line drawn from (–2, 7) to (3, –8)
Question 6 IGCSE Jan 2019 1F Q12
[3 marks]
On the grid, draw the graph of y = 2x - 3 for values of x from -1 to 4
yx−11234O−7−6−5−4−3−2−11234567
Worked Solution & Answer
x = -1 ⇒ y = -5 M1
x = 0 ⇒ y = -3 M1
x = 4 ⇒ y = 5. A1
yx−11234O−7−6−5−4−3−2−11234567
Answer: Line drawn through (−1, −5), (0, −3), (1, −1), (2, 1), (3, 3), (4, 5)
Question 7 IGCSE Jun 2018 2FR Q14
[3 marks]
On the grid, draw the graph of y = 2x + 3 for values of x from -2 to 4
–2–11234–3–2–1123456789101112O
Worked Solution & Answer
Points: (–2, –1), (–1, 1), (0, 3), (1, 5), (2, 7), (3, 9), (4, 11) M2 A1
–2–11234–3–2–1123456789101112O
Answer: Line drawn from (–2, –1) to (4, 11)
Question 8
[3 marks]
On the grid, draw the graph of y = 4x - 1 for values of x from –2 to 2
xyO–2–112–10–9–8–7–6–5–4–3–2–112345678
Worked Solution & Answer
Points: (–2, –9), (–1, –5), (0, –1), (1, 3), (2, 7) M2 A1
xyO–2–112–10–9–8–7–6–5–4–3–2–112345678
Answer: Straight line drawn from (–2, –9) to (2, 7)
Question 9
[3 marks]
On the grid below, draw the graph of y = 4 - x for values of x from -2 to 4
xy–2–11234–2–11234567O
Worked Solution & Answer
Points (–2, 6), (0, 4), (4, 0) joined with a straight line M2 A1
xy–2–11234–2–11234567O
Answer: Straight line drawn from (–2, 6) to (4, 0)
Question 10
[4 marks]
(a) Complete the table of values for y = 4x – 6 for x from –1 to 4. (2) (b) Draw the graph of y = 4x – 6 on the grid. (2)
(a) Complete the table of values for y = 4x - 6 [2 marks]
x–101234y–210
(b) On the grid, draw the graph of y = 4x - 6 for values of x from -1 to 4 [2 marks]
–11234O–14–12–10–8–6–4–22468101214yx
Worked Solution & Answer
(a)
x = –1 ⇒ y = –10 M1
x = 0 ⇒ y = –6
x = 2 ⇒ y = 2
x = 3 ⇒ y = 6 A1
x–101234y–10–6–22610
Answer (a): –10, –6, (–2), 2, 6, (10)
(b)
x = –1 ⇒ y = –10 M1
x = 0 ⇒ y = –6
x = 2 ⇒ y = 2
x = 3 ⇒ y = 6 A1
–11234O–14–12–10–8–6–4–22468101214yx
Answer (b): Straight line drawn from (–1, –10) to (4, 10)
Score: 0 / 10 (0 / 29 marks)
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