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Indices (index laws) Quiz

Grade 4 • 4B • 10 Questions (30 Marks)

Score: 0 / 10
Indices (index laws) — Notes & Worked Examples Show / Hide

Explanation:

Learn the four core index laws for powers with the same base: (1) Multiply → add powers: am × an = am+n;   (2) Divide → subtract powers: am ÷ an = am−n;   (3) Brackets → multiply powers: (am)n = amn;   (4) Power of zero: a0 = 1.

When an expression includes normal numbers (coefficients) in front of the letters, treat the numbers as normal numbers (multiply, divide, or raise them to the power) and apply the index laws to the powers!

Example 1: Simplify:
(a) y7 × y4y3      (b) (2x3y5)4

Solution:

(a) Top: y7+4 = y11; then y11−3 = y8
(b) Raise 2 to power 4: 24 = 16
Multiply powers: x3×4y5×4 = x12y20
Answer: (a) y8   (b) 16x12y20

Example 2: Simplify 18a6b23a2b5 and find the value of n in 5n × 53 = 511.

Solution:

Numbers: 18 ÷ 3 = 6; Powers: a6−2 = a4, b2−5 = b−3
For 5n × 53 = 511: n + 3 = 11 → n = 8
Answer: 6a4b−3 (or 6a4b3) and n = 8
Question 1
[1 mark]
Simplify:
6x4 × 6x3
Worked Solution & Answer
Multiply the numbers and add the powers of matching letters.
e.g. 3b2 × 4b5 = 12b7
36x7
Answer: 36x7
Question 2
[1 mark]
Simplify:
20y95y5
Worked Solution & Answer
When dividing with the same base, subtract the powers.
e.g. b7 ÷ b3 = b4
4y4
Answer: 4y4
Question 3 AQA Nov 2024 1H Q22
[3 marks]
@@TABULAR0@@
Match each expression on the left to the correct expression on the right.
One has been done for you.
7–n72n7n + 1712n7x1x12xxx2
Given 7ⁿ = x, match 7⁻ⁿ, 7²ⁿ, 7ⁿ⁺¹, 7 {}1/2 n) to 7x, 1/x, 1/2 x, √x, x². [3 marks]
Worked Solution & Answer
7²ⁿ = (7ⁿ)² = x². M1
7ⁿ⁺¹ = 7¹ × 7ⁿ = 7x. M1
7 {}1/2 n) = (7ⁿ) {}1/2) = √x. A1
7–n72n7n + 1712n7x1x12xxx2
Answer: 7²ⁿ → x², 7ⁿ⁺¹ → 7x, 7^(1/2 n) → √x
Question 4 AQA Nov 2019 1F Q27 / 1H Q8
[3 marks]
Write 27 × (32)7 as a single power of 3
Write your answer in the form 3n
Answer
Worked Solution & Answer
27 = 33. M1
(32)7 = 3^{2 × 7} = 3^{14}. M1
27 × (32)7 = 33 × 3^{14} = 3^{3 + 14} = 3^{17}. A1
Answer: Answer 317
Question 5
[3 marks]
(a) Simplify fully 2x³y⁵ × 7x²y (2)
(b) Simplify (m²)⁻³ (1)
(a) Simplify fully 2x3y5 × 7x2y [2 marks]
(b) Simplify (m2)^{-3} [1 mark]
Worked Solution & Answer
(a)
2×7 = 14, x³⁺² = x⁵, y⁵⁺¹ = y⁶ M1 A1
Answer (a): 14x5y6
(b)
m²×⁻³ = m⁻⁶ B1
Answer (b): m-6
Question 6
[3 marks]
(a) Simplify (p²)⁵ (1) (b) Simplify 12x⁷y³ ÷ 6x³y (2)
(a) Simplify (p2)5 [1 mark]
(b) Simplify 12x7y3 ÷ 6x3y [2 marks]
Worked Solution & Answer
(a)
p {}2×5) = p¹⁰ B1
Answer (a): p10
(b)
(12÷6) × x⁷⁻³ × y³⁻¹ = 2x⁴y² M1 A1
Answer (b): 2x4y2
Question 7 OCR Jun 2022 3F Q8
[3 marks]
Work out
(a) Simplify.
2 × 3a
(b) Simplify.
2x54x
(a) Simplify.
2 × 3a
[1 mark]
(b) Simplify.
2x54x
[2 marks]
Worked Solution & Answer
(a)
2 × 3a = 6a. B1
Answer (a): 6a
(b)
2/4 = 1/2 and x⁵ ÷ x = x⁴ M1
⇒ x⁴ / 2 (or 0.5x⁴). A1
Answer (b): x42
Question 8 IGCSE Nov 2023 2H Q12
[4 marks]
(a) 2⁷ × 4⁵ = 4ˣ, find x (2) (b) Simplify fully (125p⁶y²⁴) {}2/3) (2)
(a) Calculate the value of x [2 marks]
x =
(b) Simplify fully (125p6y^{24})^{23} [2 marks]
Worked Solution & Answer
(a)
2⁷ × 2¹⁰ = 2²ˣ M1
⇒ 2x = 17
⇒ x = 8.5 A1
Answer (a): x = 8.5
(b)
125 {}2/3) p {}6×2/3) y {}24×2/3) = 25p⁴y¹⁶ M1 A1
Answer (b): 25p4y^{16}
Question 9 IGCSE Jun 2025 1F Q21 / 1H Q4
[4 marks]
(a) x⁵ × x⁷ = xᵐ, find m. (1) (b) y⁸ ÷ y³ = yⁿ, find n. (1) (c) Simplify fully (5a⁴r²)³. (2)
(a) Find the value of m [1 mark]
m =
(b) Find the value of n [1 mark]
n =
(c) Simplify fully (5a4r2)3 [2 marks]
Worked Solution & Answer
(a)
5 + 7 = 12 B1
Answer (a): m = 12
(b)
8 – 3 = 5 B1
Answer (b): n = 5
(c)
5³ a {}4×3) r {}2×3) = 125a¹²r⁶ M1 A1
Answer (c): 125a12r6
Question 10 Eduqas Jun 2024 2F Q17 / 2H Q2
[5 marks]
(a) Factorise x2 - 5x - 24.
(b) Simplify (3h2)3.
(c) Represent the inequality -2 < x ≤ 3 on the number line below.
(a) Factorise x2 - 5x - 24. [2 marks]
(b) Simplify (3h2)3. [2 marks]
(c) Represent the inequality -2 < x ≤ 3 on the number line below. [1 mark]
x–4–3–2–101234
Worked Solution & Answer
(a)
Two numbers that multiply to -24 and add to -5 are -8 and 3: (x - 8)(x + 3). M1 A1
Answer (a): (x - 8)(x + 3)
(b)
33 × (h2)3 = 27h^{2 × 3} = 27h6. M1 A1
Answer (b): 27h6
(c)
< requires an empty circle at -2
≤ requires a solid circle at 3
line connects them. B1
x–4–3–2–101234
Answer (c): Open circle at -2, filled circle at 3, connected with a line
Score: 0 / 10 (0 / 30 marks)
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