(a) Circle the value of \sin 30°.
12 √(3)2 13 √(3)3 14
(b) Here is a right-angled triangle.
12 √(3)2 13 √(3)3 14 [1 mark]
Worked Solution & Mark Scheme (3 marks)
⇒ x = 24 × sin 30° = 24 × 1/2 = 12. A1
Home > Worksheets > GCSE questions by topic > Exact trig. values
Free Printable Exact trig. values PDF Worksheets, Revision Guide & GCSE Past Paper Questions (Grade 5)
Download free exact trig. values worksheets (PDF), GCSE maths past paper questions and worked solutions for Exact trig. values (5V). This is a Grade 5 geometry topic from the GCSE questions by topic collection for Foundation and Higher tier crossover GCSE Maths (Edexcel, AQA, OCR and IGCSE).
The free PDF worksheets table below brings together printable question booklets (Qs) and worked answers or mark schemes (Ans) from Maths Genie, Corbett Maths, Maths Made Easy, M4ths.com, 1st Class Maths, Dr Austin, Naiker Maths, Metatutor, E Classroom and PMT, along with past paper question booklets.
Below the worksheet links you can read our exact trig. values revision notes and worked examples with diagrams, try real GCSE past paper exact trig. values questions with step-by-step solutions, or download a PDF of all exact trig. values worksheet links.
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1st Class Maths (Edxl)
Edexcel exam questions & solutions
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1st Class Maths (AQA)
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GCSE past paper questions & solutions
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GCSE topic booklet & answers
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PMT (Edxl)
Edexcel GCSE topic questions & solutions
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PMT (AQA)
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PMT (IGCSE)
Edexcel IGCSE topic questions & solutions
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Explanation:
For non-calculator exams, recall the exact values of sin θ, cos θ, and tan θ for 0°, 30°, 45°, 60°, and 90°. Derive them anytime from an isosceles right-angled triangle (legs 1, 1, hypotenuse √2) and an equilateral triangle of side 2 split in half (sides 1, √3, 2).
| θ | 0° | 30° | 45° | 60° | 90° |
|---|---|---|---|---|---|
| sin θ | 0 | 12 | √22 | √32 | 1 |
| cos θ | 1 | √32 | √22 | 12 | 0 |
| tan θ | 0 | √33 | 1 | √3 | — |
Example 1: Work out the exact value of sin 30° + cos 60° + tan 45°.
Solution:
Example 2: Find the exact side x opposite 60° in a right-angled triangle with hypotenuse 12 cm.
Solution: