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Free Printable Probability PDF Worksheets, Revision Guide & GCSE Past Paper Questions (Grade 4)

Download free probability worksheets (PDF), GCSE maths past paper questions and worked solutions for Probability (4V). This is a Grade 4 probability topic from the GCSE questions by topic collection for Foundation and Higher tier crossover GCSE Maths (Edexcel, AQA, OCR and IGCSE).

The free PDF worksheets table below brings together printable question booklets (Qs) and worked answers or mark schemes (Ans) from Maths Genie, Corbett Maths, Maths Made Easy, Dr Frost, Naiker Maths, Dr Austin, Maths4EveryOne, Metatutor, GCSE Maths Rocket, E Classroom and PMT, along with past paper question booklets.

Below the worksheet links you can read our probability revision notes and worked examples with diagrams, try real GCSE past paper probability questions with step-by-step solutions, or download a PDF of all probability worksheet links.

Free Probability PDF Worksheets & Answers

Grade 4 • Topic 4V
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GCSE Maths Grade 4 Revision Notes & Method

Guide to Probability: Explanation, Diagrams & Worked Examples

Download Printable One Page Guide (PDF)

Explanation:

Probabilities must always be written as a fraction, decimal, or percentage between 0 and 1 (never write a probability as a ratio like 1 : 4 or in words). For mutually exclusive events (events that cannot happen at the same time), all probabilities in a table add up to 1, and P(not A) = 1 − P(A).

To find the expected number of successes in N trials, use the formula: Expected Frequency = Probability × Number of Trials.

Example 1: A biased spinner lands on Red, Blue, Green, or Yellow. P(Red) = 0.25, P(Blue) = 0.15, and P(Green) is twice P(Yellow). Find P(Green).

Solution:

Remaining probability = 1 − (0.25 + 0.15) = 0.60
Let P(Yellow) = x and P(Green) = 2x:
x + 2x = 0.60 → 3x = 0.60 → x = 0.20
P(Green) = 2 × 0.20 = 0.40 → Answer: 0.4

Example 2: The spinner in Example 1 is spun 300 times. Work out an estimate for the number of times it lands on Red.

Solution:

Expected frequency = P(Red) × Number of spins
= 0.25 × 300
= 75
Answer: 75 times
Scanned GCSE Exam Questions & Worked Solutions

GCSE Past Paper Probability Questions & Answers

Past Paper Example 1 OCR Nov 2022 2F Q19 / 5H Q3 3 marks
Azmi has a fair spinner numbered 2, 5 and 8.
258
(a) Complete the table to show all of the possible totals. [1 mark]
First spinSecondspinTotal258247571081316
(b) Find the probability that the total is a square number. [2 marks]
Worked Solution & Mark Scheme (3 marks)
Part (a) Solution:
2 + 8 = 10
5 + 8 = 13
8 + 2 = 10. B1
Answer (a): Missing totals: 10 (row 2, col 8), 13 (row 5, col 8), 10 (row 8, col 2)
Part (b) Solution:
The 9 equally likely totals are 4, 7, 10, 7, 10, 13, 10, 13, 16 M1
The square numbers are 4 and 16 (2 outcomes out of 9) ⇒ probability = 2/9. A1
Answer (b): 29
Past Paper Example 2 AQA Nov 2024 1F Q9 6 marks
A number is picked at random from the first three positive odd numbers.
A number is picked at random from the first four prime numbers.
The two numbers are **multiplied** to get a score.
(a) Complete the table. [4 marks]
primeodd×2371515
(b) What is the probability that the score is a square number?
Give your answer as a fraction.
[2 marks]
Worked Solution & Mark Scheme (6 marks)
Part (a) Solution:
Odd numbers: 1, 3, 5. Prime numbers: 2, 3, 5, 7. Multiply each pair M3 A1
primeodd×2371515532357691521102535
Answer (a): Headers 3 and 5; cells 2,3,5,7 / 6,9,15,21 / 10,15,25,35
Part (b) Solution:
Out of 12 outcomes, the square numbers are 9 and 25 (2 outcomes), giving 212 (or 16) M1 A1
Answer (b): Answer 212
Past Paper Example 3 AQA Jun 2023 2F Q18 / 2H Q7 5 marks
In a game,
• an ordinary fair six-sided dice is rolled
• the fair spinner shown is spun.
2x3xx2
The score is the dice number **substituted** into the spinner expression.
(a) Complete the table to show all of the possible scores.
@@TABULAR0@@
[2 marks]
(b) A player wins the game if their score is 10 or more.
Work out the probability that they win the game.
[1 mark]
(c) The game is played 711 times.
Estimate the number of games that are won.
[2 marks]
Worked Solution & Mark Scheme (5 marks)
Part (a) Solution:
Substitute x = 1, 2, 3, 4, 5, 6 into 2x, 3x and x² M1 A1
Answer (a): Row 2x: 2, 4, 6, 8, 10, 12; Row 3x: 3, 6, 9, 12, 15, 18; Row x²: 1, 4, 9, 16, 25, 36
Part (b) Solution:
Scores ⩾ 10 are 10, 12 (in 2x), 12, 15, 18 (in 3x), and 16, 25, 36 (in x²) → 8 out of 18 = 8/18 (or 4/9) B1
Answer (b): Answer 818
Part (c) Solution:
711 × 8/18 = 711 × 4/9 = 316 M1 A1
Answer (c): Answer 316

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