Free Printable Real life graphs PDF Worksheets, Revision Guide & GCSE Past Paper Questions (Grade 4)
Download free real life graphs worksheets (PDF), GCSE maths past paper questions and worked solutions for Real life graphs (4D). This is a Grade 4 algebra topic from the GCSE questions by topic collection for Foundation and Higher tier crossover GCSE Maths (Edexcel, AQA, OCR and IGCSE).
On a distance–time graph, a sloping straight line represents constant speed, a horizontal flat line means the object is stationary (stopped), and the gradient equals the speed (DistanceTime). Always check the time scale on the horizontal axis (e.g. 15 mins = 0.25 hours).
On a cost or conversion graph (such as taxi fares or utility bills), the y-intercept is the fixed standing charge, and the gradient (Change in yChange in x) is the rate per unit (e.g. cost per mile).
Example 1: A cyclist leaves at 09:00, travels 18 km by 09:45, rests 15 mins, then cycles 18 km home by 10:30. Find Stage 1 speed in km/h.
Dist = 18 km
45 min = 0.75 h
Speed = 180.75 = 24 km/h
Example 2: A plumber's graph goes from (0, 45) through (3, 135) for hours x and cost y (£). Find the call-out fee and hourly rate.
Fee (0 hrs) = £45
Rate = 135 − 453 = £30/h
Scanned GCSE Exam Questions & Worked Solutions
GCSE Past Paper Real life graphs Questions & Answers
Scarlett leaves home at 10.00 to cycle to the supermarket. Here is part of a distance-time graph of her trip to the supermarket.
(a)She arrives at the supermarket at 10.20 How far is the supermarket from her home?[1 mark]
(b)She leaves the supermarket at 10.35 How long does she stay at the supermarket?[1 mark]
(c)Scarlett cycles home at a constant speed using the same route. It takes her 3 minutes longer than her journey to the supermarket. Complete the distance-time graph.[2 marks]
Worked Solution & Mark Scheme (4 marks)
Part (a) Solution:
Reading the vertical axis at 10.20: distance is 7 km. B1
Answer (a): Answer 7 km
Part (b) Solution:
Time stayed = 10.35 - 10.20 = 15 minutes. B1
Answer (b): Answer 15 minutes
Part (c) Solution:
(Average speed = distance ÷ time) Outbound journey took 20 minutes (10.00 to 10.20) M1 Return journey takes 20 + 3 = 23 minutes Leaves at 10.35, arrives home at 10.35 + 23 minutes = 10.58 Draw a straight line from (10.35, 7) down to (10.58, 0). A1
Answer (c): Answer Line from (10.35, 7) to (10.58, 0)
Jenny leaves home at 06.00 She runs for 3 hours. Here is a distance-time graph of her run.
(a)How far from home is she after 3 hours?[1 mark]
(b)For the next hour she rests. She then gets a bus home. She arrives home at 11.30 Complete the distance-time graph. Assume the bus travels at a constant speed.[2 marks]
Worked Solution & Mark Scheme (3 marks)
Part (a) Solution:
At 09.00 (3 hours after 06.00), read the distance from the vertical axis: 20 km. B1
Answer (a): Answer 20 km
Part (b) Solution:
(Average speed = distance ÷ time) Resting for 1 hour: draw a horizontal line at 20 km from 09.00 to 10.00 M1 Bus travels home: draw a straight line from (10.00, 20) to (11.30, 0). A1
Answer (b):Horizontal line from (09.00, 20) to (10.00, 20), then a straight line from (10.00, 20) to (11.30, 0).