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Surds

Free Printable Surds PDF Worksheets, Revision Guide & GCSE Past Paper Questions (Grade 7)

Download free surds worksheets (PDF), GCSE maths past paper questions and worked solutions for Surds (7A). This is a Grade 7 number topic from the GCSE questions by topic collection for Higher tier GCSE Maths (Edexcel, AQA, OCR and IGCSE).

The free PDF worksheets table below brings together printable question booklets (Qs) and worked answers or mark schemes (Ans) from Maths Genie, Maths4Everyone, Corbett Maths, Maths Made Easy, Dr Frost, 1st Class Maths, Metatutor, Maths Takeaway, Dr Austin, GCSE Maths Rocket, Maths DIY, IGCSE MT, E Classroom and PMT, along with past paper question booklets.

Below the worksheet links you can read our surds revision notes and worked examples with diagrams, try real GCSE past paper surds questions with step-by-step solutions, or download a PDF of all surds worksheet links.

Free Surds PDF Worksheets & Answers

Grade 7 • Topic 7A
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GCSE Maths Grade 7 Revision Notes & Method

Guide to Surds: Explanation, Diagrams & Worked Examples

Download Printable One Page Guide (PDF)

Explanation:

A surd is an irrational root that cannot be written as an exact fraction, such as √2, √3, or √5. To simplify a surd, split the number under the root into its largest square factor multiplied by another factor using √(ab) = √a × √b, and only collect like surds when adding or subtracting.

To rationalise the denominator of a fraction, remove the surd from the bottom: for a√b, multiply top and bottom by √b; for ca + √b, multiply top and bottom by the conjugate a − √b so the middle surd terms cancel out via the difference of two squares.

Example 1: Simplify fully √75 + √48 − 2√12

Solution:

Extract the largest square factor from each surd:
√75 = √25 × √3 = 5√3
√48 = √16 × √3 = 4√3
2√12 = 2 × √4 × √3 = 2 × 2√3 = 4√3
5√3 + 4√3 − 4√3 = 5√3
Answer: 5√3

Example 2: Rationalise the denominator of 143 − √2

Solution:

Multiply numerator and denominator by 3 + √2:
= 14(3 + √2)(3 − √2)(3 + √2)
Denominator: 32 − (√2)2 = 9 − 2 = 7
= 14(3 + √2)7 = 2(3 + √2)
Answer: 6 + 2√2
Scanned GCSE Exam Questions & Worked Solutions

GCSE Past Paper Surds Questions & Answers

Past Paper Example 1 GCSE May 2024 1H Q17 3 marks
(a) Rationalise the denominator of 1/√7 (1) (b) Simplify fully √80 – √5 (2)
(a) Rationalise the denominator of 1√(7) [1 mark]
(b) Simplify fully √(80) - √(5) [2 marks]
Worked Solution & Mark Scheme (3 marks)
Part (a) Solution:
(1 × √7)/(√7 × √7) = √7/7 B1
Answer (a): √(7)7
Part (b) Solution:
√80 – √5 = √(16 × 5) – √5 = 4√5 – √5 = 3√5 M1 A1
Answer (b): 3√(5)
Past Paper Example 2 AQA Nov 2024 1H Q20 4 marks
(a) Show that √363 / √3 simplifies to an integer. [2 marks]
20 (b) Rationalise the denominator and simplify 20 / √5. [2 marks]
(a) Show that √(363)√(3) simplifies to an integer. [2 marks]
(b) Rationalise the denominator and simplify 20√(5) [2 marks]
Worked Solution & Mark Scheme (4 marks)
Part (a) Solution:
√363 / √3 = √(363 ÷ 3) = √121 = 11 M1 C1
Answer (a): √(363/3) = √121 = 11
Part (b) Solution:
(20 / √5) × (√5 / √5) = 20√5 / 5 = 4√5 M1 A1
Answer (b): Answer 4√(5)
Past Paper Example 3 AQA Jun 2023 1H Q22 3 marks
a = √(2) and b = √(18)
Match each expression to its value.
One has been done for you.
a2a + babb / a236364√210√20
a = √2 and b = √18. Match each expression (a², a + b, ab, b/a) to its value. [3 marks]
Worked Solution & Mark Scheme (3 marks)
b = √18 = 3√2. M1
a + b = √2 + 3√2 = 4√2. M1
ab = √2 × √18 = √36 = 6.
b/a = √18 / √2 = √9 = 3. A1
a2a + babb / a236364√210√20
Answer: a + b → 4√2, ab → 6, b/a → 3

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